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8c^2-40c-112=0
a = 8; b = -40; c = -112;
Δ = b2-4ac
Δ = -402-4·8·(-112)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-72}{2*8}=\frac{-32}{16} =-2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+72}{2*8}=\frac{112}{16} =7 $
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